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35x^2-24x=31
We move all terms to the left:
35x^2-24x-(31)=0
a = 35; b = -24; c = -31;
Δ = b2-4ac
Δ = -242-4·35·(-31)
Δ = 4916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4916}=\sqrt{4*1229}=\sqrt{4}*\sqrt{1229}=2\sqrt{1229}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{1229}}{2*35}=\frac{24-2\sqrt{1229}}{70} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{1229}}{2*35}=\frac{24+2\sqrt{1229}}{70} $
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